This program returns true if the number is in the array list more than once.
My Code
import java.util.ArrayList;
import java.util.Scanner;
public class MoreThanOnce {
public static boolean moreThanOnce(ArrayList<Integer> list, int searched) {
// write your code here
int tf = 0;
for (int num : list) {
if (num == searched) {
tf++;
}
if (tf == 2) {
return true;
}
}
return false;
}
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
ArrayList<Integer> list = new ArrayList<Integer>();
list.add(3);
list.add(2);
list.add(7);
list.add(2);
System.out.println("Type a number: ");
int number = Integer.parseInt(reader.nextLine());
if (moreThanOnce(list, number)) {
System.out.println(number + " appears more than once.");
} else {
System.out.println(number + " does not appear more than once. ");
}
}
}
Model Code
import java.util.ArrayList;
import java.util.Scanner;
public class MoreThanOnce {
public static boolean moreThanOnce(ArrayList<Integer> list, int searched) {
// write your code here
int howMany = 0;
for (int numberInList : list) {
if (numberInList == searched) {
howMany = howMany + 1;
}
if (howMany > 1) {
return true;
}
}
return false;
}
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
ArrayList<Integer> list = new ArrayList<Integer>();
list.add(3);
list.add(2);
list.add(7);
list.add(2);
System.out.println("Type a number: ");
int number = Integer.parseInt(reader.nextLine());
if (moreThanOnce(list, number)) {
System.out.println(number + " appears more than once.");
} else {
System.out.println(number + " does not appear more than once. ");
}
}
}
Comments
🙂 Isn’t it great when you think you’ve missed something but then the model code does it the same way. Although looking back i have made a mistake.
if (tf == 2) {
return true;
}should be….
if (tf > 1) {
return true;
}Otherwise if the number appears three times it would return false.